4x^2-10x=204

Solution for 4x^2-10x=204 equation:

4x^2-10x=204

We move all terms to the left:

4x^2-10x-(204)=0

a = 4; b = -10; c = -204;
Δ = b2-4ac
Δ = -102-4·4·(-204)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-58}{2*4}=\frac{-48}{8}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+58}{2*4}=\frac{68}{8}
=8+1/2
$